Time taken (tt) = 15 minutes = 15 × 60 seconds = 900 seconds
       Speed (vv) = 2 m/s
   Formula:
       Distance (dd) = Speed × Time
       d=v×td=v×t
   Calculation:
       d=2 m/s×900 s=1800 md=2m/s×900s=1800m
   Answer: The distance between Geetha’s house and the school is 1800 meters (1.8 km).
Q- A car starts from rest and it is travelling with a velocity of 20 m/s in 10 s. What is its acceleration?
   Given:
       Initial velocity (uu) = 0 m/s
       Final velocity (vv) = 20 m/s
       Time (tt) = 10 seconds
   Formula:
       Acceleration (aa) = ΔvttΔv​
       ΔvΔv = v−uv−u
   Calculation:
       Δv=20 m/s−0 m/s=20 m/sΔv=20m/s−0m/s=20m/s
       a=20 m/s10 s=2 m/s2a=10s20m/s​=2m/s2
   Answer: The acceleration of the car is 2 m/s².
Q- A bus can accelerate with an acceleration of 1 m/s². Find the minimum time for the bus to attain the speed of 100 km/h from 50 km/h.
   Given:
       Initial speed (uu) = 50 km/h = 50×10003600360050×1000​ m/s = 500003600360050000​ m/s ≈ 13.89 m/s
       Final speed (vv) = 100 km/h = 100×100036003600100×1000​ m/s = 10000036003600100000​ m/s ≈ 27.78 m/s
       Acceleration (aa) = 1 m/s²
   Formula:
       Time (tt) = ΔvaaΔv​
       Δv=v−uΔv=v−u
   Calculation:
       Δv=27.78 m/s−13.89 m/s=13.89 m/sΔv=27.78m/s−13.89m/s=13.89m/s
       t=13.89 m/s1 m/s2=13.89 st=1m/s213.89m/s​=13.89s
   Answer: The minimum time for the bus to attain the speed of 100 km/h from 50 km/h is approximately 13.89 seconds.
