# Class 6 Maths Chapter 2 Solutions

## Class 6 Chapter 2 Whole Numbers

NCERT Solutions for Class 6 Maths Chapter 2 | NCERT class 6 Maths solutions provided for students by our expert teachers .

Class 6 Maths Chapter 2 Exercise 2.1 Solutions

1. Write the next three natural numbers after 10999.

Solution :- Next 3 Natural Numbers Are 11000,11001,11002

1. Write the three whole numbers occurring just before 10001.

Solution :- Next 3 Whole Numbers Are 10000,9999,9998

1. Which is the smallest whole number?

Solution :- Zero  is the smallest whole number.

1. How many whole numbers are there between 32 and 53?

Solution :- there are total 20 whole numbers are there in between 32 and 53.

1. Write the successor of:

(a) 2440701 (b) 100199 (c) 1099999 (d) 2345670

Solution :-

2440701 + 1 =  2440702

100199 + 1 = 100200

1099999 + 1 = 1100000

2345670 + 1 = 2345671

1. Write the predecessor of:

(a) 94 (b) 10000 (c) 208090 (d) 7654321

Solution :-

predecessor of 94 = 94-1=93

predecessor of 10000 = 10000-1 = 9999

predecessor of 208090 = 208090-1=208089

predecessor of 7654321 =  7654321-1 = 7654320

1. In each of the following pairs of numbers, state which whole number is on the left of the other number on the number line. Also write them with the appropriate sign (>, <) between them.

530, 503 (b) 370, 307 (c) 98765, 56789 (d) 9830415, 10023001

Solution:-

(a) 530 > 503; So, On the number line, 503 appears to the left of 530.

(b) 370 > 307; So, On the number line, 307 appears to the left of 370.

(c) 98765 > 56789; So, On the number line, 56789 appears to the left of 98765.

(d) 9830415 < 10023001; So, On the number line, 9830415 appears to the left of 10023001.

1. Which of the following statements are true (T) and which are false (F):

(a) Zero is the smallest natural number. [ F ]

(b) 400 is the predecessor of 399. [ F ]

(c) Zero is the smallest whole number. [ T ]

(d) 600 is the successor of 599. [ T ]

(e) All-natural numbers are whole numbers. [ T ]

(f) All whole numbers are natural numbers. [ F ]

(g) The predecessor of a two-digit number is never a single digit number. [ F ]

(h) 1 is the smallest whole number. [ F ]

(i) The natural number 1 has no predecessor. [ T ]

(j) The whole number 1 has no predecessor. [ F ]

(k) The whole number 13 lies between 11 and 12. [ F ]

(l) The whole number 0 has no predecessor. [ T ]

(m) The successor of a two-digit number is always a two-digit number. [ F ]

Chapter 2 – Whole Numbers  (Ex. 2.2)

1. Find the sum by suitable rearrangement:

(a) 837 + 208 + 363

Solution :-

If we use associative property then we add 837+363 first

• [837+363] + 208
• 1200+208 = 1408

(b) 1962 + 453 + 1538 + 647

With  associative property then we add

• [1962+1538]+[453+647]
• 3500+1100 = 4600

The term “associative property” refers to the grouping of numbers.

1. Find the product by suitable arrangement:
 (a) 2 x 1768 x 50  Solution – [2 x 50] x 1768 100 x 1768 = 176800 (b) 4 x 166 x 25 Solution – [4 x 25 ] x 166 100 x 166 = 16600 (c) 8 x 291 x 125 Solution – [125 x 8 ] x 291 1000 x 291 291000 (d) 625 x 279 x 16 Solution – [625 x 16 ] x 279 10000 x 279 2790000 (e) 285 x 5 x 60 Solution – 284 x [5 x 60] 284 x 300 85500 (f) 125 x 40 x 8 x 25 Solution – [125 x 8] x [40 x 25] 1000 x 1000 1000000
1. Find the value of the following:

(a) 297 x 17 + 297 x 3

Solution:-

• 297 x [17+3]
• 297 x 20
• 5940

(b) 54279 x 92 + 8 x 54279

Solution:-

• 54279 x [92+8]
• 54279 x 100
• 5427900

(c) 81265 x 169 – 81265 x 69

Solution:-

• 81265 x [169-69]
• 81265 x 100
• 8126500

(d) 3845 x 5 x 782 + 769 x 25 x 218

Solution:-

• 3845 x 5 x 782 + 769 x 5 x 5 x 218
• 3845 x 5 x 782 + [769 x 5] x 5 x 218
• 3845 x 5 x 782 + 3845 x 5 x 218
• 3845 x 5 x [782+218]
• [3845 x 5] x 1000
• 19225 x 1000
• 19225000

Find the product using suitable properties.
(a) 738 x 103

Solution:- [distributive]

• 738 x [100 + 3 ]
• 738 x100 + 738 x 3
• 73800 + 2214
• 76014

(b) 854 x 102
Solution:- [distributive]

• 854 x [100 + 2]
• 854 x 100 + 854 x 2
• 85400 + 1708
• 87108

(c) 258 x 1008
Solution:- [distributive]

• 258 x [1000 + 8 ]
• 258 x 1000 + 258 x 8
• 258000 + 2064
• 260064

(d) 1005 x 168

Solution:- [distributive]

• [1000 + 5 ] x 168
• 1000 x 168 + 5 x 168
• 168000 + 840
• 168840

Note :- The distributive property is a multiplication property that is applied in both addition and subtraction.

1. A taxi-driver, filled his car petrol tank with 40 liters of petrol on Monday. The next day, he filled the tank with 50 liters of petrol. If the petrol costs  44 per liter, how much did he spend in all on petrol?

Solution :-

• On Monday Petrol filled – 40 liters.
• On Next day – 50 liters
• Total petrol = 40+50 = 90
• Price for 1-liter petrol is 44 so the price for 90-liter petrol will be
• 44 x 90 =  3960.00
• So, he spends 3960 Rs. On petrol.

1. A vendor supplies 32 liters of milk to a hotel in a morning and 68 liters of milk in the evening. If the milk costs ` 15 per liter, how much money is due to the vendor per day?

Solution:-

• Milk in Morning = 32 liters
• Milk in evening = 68 liters
• Total milk per day = 32+68 = 100
• Price of 1 liter of milk = 15
• 100 liter milk price = 100 x 15 = 1500
• Money due to the vendor per day is rs 1500

Also Check :-

Chapter 1 Solutions

Class 6 Olympiad Previous Year Papers